2x^{2}+xy= 1 & & \\
\frac{9x^{2}}{2(1-x)^{4}}= 1+\frac{3xy}{2(1-x)^{2}} & &
\end{matrix}\right.$
Edited by BoFaKe, 15-07-2012 - 20:17.
Edited by BoFaKe, 15-07-2012 - 20:17.
TXĐ: x khác 1Giải hệ phương trình sau :$\left\{\begin{matrix}
2x^{2}+xy= 1 & & \\
\frac{9x^{2}}{2(1-x)^{4}}= 1+\frac{3xy}{2(1-x)^{2}} & &
\end{matrix}\right.$
Edited by minh29995, 15-07-2012 - 20:37.
0 members, 1 guests, 0 anonymous users