Tìm $\min P = \frac{{{x^2}}}{y} + \frac{{{y^2}}}{x}$
Edited by Ispectorgadget, 29-07-2012 - 20:18.
Edited by Ispectorgadget, 29-07-2012 - 20:18.
Dân Thanh Hóa ăn rau má phá đường tàu
Áp dụng bđt $\text{ Cauchy Schwarz dạng Engel}$ ta cóCho $x,y>0$, $x+y \ge 4$
Tìm $\min P = \frac{{{x^2}}}{y} + \frac{{{y^2}}}{x}$
Cách 2: P = $\frac{{{x^2}}}{y} + y + \frac{{{y^2}}}{x} + x - (x + y) \geq 2(x+y)-(x+y)=x+y\geq 4$Cho $x,y>0$, $x+y \ge 4$
Tìm $\min P = \frac{{{x^2}}}{y} + \frac{{{y^2}}}{x}$
Edited by binhmetric, 29-07-2012 - 20:36.
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