Cho tam giác ABC .Tìm Min của P =$3\sin ^{2}\frac{A}{2} +4\sin ^{3}\frac{B}{2}+6\sin ^{4}\frac{C}{2}$
Cho tam giác ABC .Tìm Min của P =$3\sin ^{2}\frac{A}{2} +4\sin ^{3}\frac{B}{2}+6\sin ^{4}\frac{C}{2}$
Started By kieutorres, 09-11-2012 - 11:54
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Posted 09-11-2012 - 11:54
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