$\frac{1}{{{a^2} + bc}} + \frac{1}{{{b^2} + ac}} + \frac{1}{{{c^2} + ab}} \le \frac{{a + b + c}}{{2abc}}$
Edited by CelEstE, 19-11-2012 - 23:11.
Edited by CelEstE, 19-11-2012 - 23:11.
Freedom Is a State of Mind
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