P=$\frac{a}{b}+2\sqrt{1+\frac{b}{c}}+3\sqrt[3]{1+\frac{c}{a}}$
Edited by duc321999real, 03-03-2013 - 21:29.
Bài toán cực hay. Tìm Min P=$\frac{a}{b}+2\sqrt{1+\frac{b}{c}}+3\sqrt[3]{1+\frac{c}{a}}$
Started By duc321999real, 03-03-2013 - 21:27
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Posted 03-03-2013 - 21:27
duc321999real
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Cho a;b;c>0 và a$\geq$ Max (b,c) .Tìm Min
P=$\frac{a}{b}+2\sqrt{1+\frac{b}{c}}+3\sqrt[3]{1+\frac{c}{a}}$
P=$\frac{a}{b}+2\sqrt{1+\frac{b}{c}}+3\sqrt[3]{1+\frac{c}{a}}$
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