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$\left [ \frac{(n-1)!}{n} \right ]\vdots n-1$

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#1
nhatquangsin

nhatquangsin

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CM$\left [ \frac{(n-1)!}{n} \right ]\vdots n-1$ với $n\geq 5$

 



#2
PRONOOBCHICKENHANDSOME

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$(n-1,n)=1 , (n-1)! \vdots n \Rightarrow \frac{(n-1)!}{n} \vdots (n-1)$ 


Edited by PRONOOBCHICKENHANDSOME, 11-06-2013 - 20:11.





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