Bài toán: Chứng minh rằng:
$$\lim_{n \to +\infty}\left(\frac{2}{3}\right)^{n}\sum_{k=0}^{\left\lfloor \frac{n}{3} \right\rfloor}\binom{n}{k}2^{-k}=\frac{1}{2}$$
Edited by dark templar, 17-06-2013 - 20:45.
$\lim_{n \to +\infty}\left(\frac{2}{3}\right)^{n}\sum_{k}\binom{n}{k}2^{-k}=\frac{1}{2}$
Started By dark templar, 17-06-2013 - 20:44
combinatorial limit
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Posted 17-06-2013 - 20:44
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combinatorial limit
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Tính $\lim_{n \to \infty}\frac{1}{n^2}\sum_{k=0}^{n}\ln \binom{n}{k}$.Started by dark templar, 23-05-2013  combinatorial limit
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