$1)$ $(2x^2-2x+1)\sqrt{2x-1} +(8x^2-8x+1)\sqrt{-x^2+x}=0$
2) $2\sqrt{x+2}-\sqrt{x^2+x+1}=x^2+6x+6$3) $\sqrt{6+12x+5x^2-x^3}-\sqrt{3x^3+4x^2+2x+1}+12x+8=\frac{x^4}{x+1}$
câu 1 hàm nè
$\frac{\sqrt{2x-1}}{2(4x^2-4x+1)-1}=\frac{\sqrt{x-x^2}}{2(x-x^2)-1}$
- nguyenquangtruonghktcute yêu thích