$\Leftrightarrow 2sinx =sin^2x (3-4sin^2x)^2 $Giải pt
$sinx=\frac{1}{2}sin^23x$.
*$sinx=0 $
*$sinx\neq 0$
$\Leftrightarrow sinx(16sin^4x - 24sin^2x +9 )=2 $
$\Leftrightarrow 16sin^5x -24sin^3x+9sinx - 2 =0$
có nghiệm $sinx=\frac{1}{2}$
20-09-2012 - 15:44
$\Leftrightarrow 2sinx =sin^2x (3-4sin^2x)^2 $Giải pt
$sinx=\frac{1}{2}sin^23x$.
19-09-2012 - 16:50
$\Leftrightarrow sin^2x-sinxsin^23x + \frac{1}{4}sin^43x -\frac{1}{4}sin^43x +\frac{1}{4}sin^23x=0$Giải pt
$\sin^2x+\frac{1}{4}\sin^23x=sinx.\sin^23x$
19-09-2012 - 16:39
17-09-2012 - 15:03
16-09-2012 - 20:35
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