Cho $a,b,c> 0$. Chứng minh rằng $\frac{a^{3}}{b}+\frac{b^{3}}{c}+\frac{c^{3}}{a}\geq ab+bc+ca$
Cho $a,b,c> 0$. Chứng minh rằng $\frac{a^{3}}{b}+\frac{b^{3}}{c}+\frac{c^{3}}{a}\geq ab+bc+ca$
Started By phuonganh2003, 11-11-2016 - 17:35
#1
Posted 11-11-2016 - 17:35
#2
Posted 11-11-2016 - 17:45
$(\frac{a^{3}}{b}+ab)+(\frac{b^{3}}{c}+bc)+(\frac{c^{3}}{a}+ac)\geq 2a^{2}+2b^{2}+2c^{2}\geq 2ab+2bc+2ac$
Edited by yeutoan2001, 11-11-2016 - 17:46.
#3
Posted 11-11-2016 - 17:53
Cho $a,b,c> 0$. Chứng minh rằng $\frac{a^{3}}{b}+\frac{b^{3}}{c}+\frac{c^{3}}{a}\geq ab+bc+ca$
Ngoài ra có thể dùng BĐT C-S cho 3 cặp số
- hailang2002 likes this
1 user(s) are reading this topic
0 members, 1 guests, 0 anonymous users