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Binh nhất
cho a1, a2,...,an >0 thỏa $\frac{1}{a1+2007}+\frac{1}{a2+2007}+...+\frac{1}{an+2007}=\frac{1}{2007}$
chứng minh $\sqrt[n]{a1a2...an}\geq 2007(n-1)$
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