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$$f(x)=\begin{equation}\int_{x}^{x+\frac{\pi}{2}}\frac{|\sin t|}{1+\sin^2 t}dt\end{equation}$$

* * * * * 1 votes tích phân & bất đẳng thức integration 2017 [d]

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DOTOANNANG

DOTOANNANG

    Đại úy

  • ĐHV Toán Cao cấp
  • 1610 posts

T í n h

$$\begin{equation}\begin{split} f(\,x\,)= \int_{\,x}^{\,x+ \frac{\pi}{2}}\,\frac{\left | \sin\,t \right |}{1+ \sin^{\,2}\,t}\,\text{d}t \end{split}\end{equation}$$

 







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