$B = 1 + \frac{1}{2} + \frac{1}{3} + \frac{1}{4} + ... + \frac{1}{{63}} < 6$
$C = \frac{1}{2}.\frac{3}{4}.\frac{5}{6}....\frac{{9999}}{{10000}} < \frac{1}{{100}}$
Edited by legialoi, 13-05-2012 - 08:17.
Edited by legialoi, 13-05-2012 - 08:17.
Edited by mituot03, 13-05-2012 - 09:24.
Chứng minh:
$C = \frac{1}{2}.\frac{3}{4}.\frac{5}{6}....\frac{{9999}}{{10000}} < \frac{1}{{100}}$
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