$M=\frac{(\sqrt{x}+\frac{1}{\sqrt{x}})^{6}-(x^{3}+\frac{1}{x^{3}})-2}{(\sqrt{x}+\frac{1}{\sqrt{x}})^{3}+x\sqrt{x}+\frac{1}{x\sqrt{x}}}$ (với $x\geq 1$)
Edited by duaconcuachua98, 22-01-2013 - 22:21.
$(\sqrt{x}+\frac{1}{\sqrt{x}})^{6}-(x^{3}+\frac{1}{x^{3}})-2$
Started By duaconcuachua98, 22-01-2013 - 22:19
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Posted 22-01-2013 - 22:19
duaconcuachua98
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$M=\frac{(\sqrt{x}+\frac{1}{\sqrt{x}})^{6}-(x^{3}+\frac{1}{x^{3}})-2}{(\sqrt{x}+\frac{1}{\sqrt{x}})^{3}+x\sqrt{x}+\frac{1}{x\sqrt{x}}}$ (với $x\geq 1$)
$M=\frac{(\sqrt{x}+\frac{1}{\sqrt{x}})^{6}-(x^{3}+\frac{1}{x^{3}})-2}{(\sqrt{x}+\frac{1}{\sqrt{x}})^{3}+x\sqrt{x}+\frac{1}{x\sqrt{x}}}$ (với $x\geq 1$)
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