$8.dk... (\sqrt{x+3}-\sqrt{x}).(\sqrt{1-x}-1)=1 <=> \frac{3}{\sqrt{x+3}+\sqrt{x}}.(\sqrt{1-x}+1)=1 <=> 3(\sqrt{1-x}+1)=\sqrt{x+3}+\sqrt{x} <=> \sqrt{1-x}\left \lfloor 3+\frac{\sqrt{1-x}}{1+\sqrt{x}} +\frac{\sqrt{1-x}}{2+\sqrt{x+3}}\right \rfloor=0 => x=1$
- Kar Kar yêu thích