1. $x^{3}+\sqrt{1-x^{3}}=x\sqrt{2-2x^2}$
2,$(\sqrt{x+3}-\sqrt{x+1})(x^{2}+\sqrt{x^{2}+4x+3})=2x$
3,$15x^{2}+2(x+1)\sqrt{x+2}=2-5x$
4,$2x+1+x\sqrt{x^2+2}+(x+1)\sqrt{x^2+2x+3}=0$
5,$2\sqrt[3]{3x-2}+3\sqrt{6-5x}-8=0$
6,$x^2-2(x+1)\sqrt{3x+1}=2\sqrt{2x^2+5x+2}-8x-5$
7,$\sqrt[4]{x-\sqrt{x^2-1}}+\sqrt{x+\sqrt{x^2+1}}=2$
8,$\sqrt{5x^2+24x+28}-\sqrt{x^2+x-20}=5\sqrt{x+2}$
8
$pt\Leftrightarrow \sqrt{5x^{2}+24x+x8}=5\sqrt{x+2}+\sqrt{x^{2}+x-20}$
$\Leftrightarrow 2x^{2}-x-1=5\sqrt{(x^{2}-2x-8)(x+5)}$
đặt $\sqrt{x^{2}+2x-8}=a,\sqrt{x+5}=b$
pt trở thành$2a^{2}+3b^{2}= 5ab$
đến đây thì dễ rồi